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Find the sum of the first 44 terms of the following series. to the nearest integer 10,14,18,...

1 Answer

6 votes

The first term is a=10.

The number of terms is n=44.

The common difference is d=4.

The formula for the sum of n terms is,


S=(n)/(2)\lbrack2a+(n-1)d\rbrack

Determine the sum of first 44 terms of the series.


\begin{gathered} S=(44)/(2)\lbrack2\cdot10+(44-1)4\rbrack \\ =22\cdot\lbrack20+172\rbrack \\ =22\cdot192 \\ =4224 \end{gathered}

So answer is 4224.

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User Rysqui
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