Question

I need help question

Answer 1

- The first integral is bounded by the x-values of [6, 22]

- The second integral is bounded by the x-values of [6, 14]

- When we are asked to find the difference between the two integrals, since, they both begin at 6, it implies that, when the second integral is taken away from the first integral, there must be some extra x-values.

- The extra values are from 14 to 22.

- Thus, we have:

`\int_6^(22)f(x)-\int_6^(14)f(x)=\int_(14)^(22)f(x)`

Final Answer

`\begin{gathered} b=22 \\ a=14 \end{gathered}`