asked 228k views
4 votes
Mary estimates the weight of her cat to be 10 pounds.the actual weight of the cat is 13.75 pounds.find the percent error.

asked
User GHH
by
8.1k points

1 Answer

5 votes

The percentage error is the ratio of the difference between the two readings and the actual

Error = 13.75 - 10

= 3.75

Percent error = 3.75/13.75

= 27.27%

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.