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1 Answer

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To answer this question, we need to evaluate each function in x=66, this way:


\begin{gathered} y=7(66) \\ y=462 \\ y=(66)^2-12(66)+84 \\ y=3648 \\ y=1.1317^(66) \\ y=3517.76 \end{gathered}

In this case, the function that has a greater value at x=66 is the one in the second option:


y=x^2-12x+84

answered
User James Adkison
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