Question

Multiply.4y=2y3v2.4v7

Answer 1

Let's recall one of the properties of exponents:

`x^4\ast x^5=x^{4\text{ + 5}}=x^9`

Therefore, in our exercise we have:

`4y\text{ }\ast2y^3=8y^{4\text{ }}andv^2\ast4v^7=4v^9`
`8y^4\ast4v^9=32y^4v^9`