Question

A balloon has a volume of 1785 mL at 25°C, if the volume of balloon changes to 1.25 L, what is the new temperature in degree Celcius atconstant pressure and amount?

Answer 1

We work here with Charles' Law. The equation used here is:

V1/T1 = V2/T2 (1)

(pressure and amount constant)

V is for volume and T for temperature

V1 = 1785 mL

1 L = 1000 mL ==> V1 = 1.785 L

T1 = 25 °C = 25 °C + 273 = 298 K

V2 = 1.25 L

T2 = unknown

From (1) we clear T2:

T2 = V2 x T1/V1 = 1.25 L x 298 K/1.785 L = 209 K approx.

T2 = 209 K - 273 = -64 °C

Answer: T2 = -64 °C