Question

Find the links of the sides of these special triangles

Answer 1

From the triangle, we express the tangent of 60° as:

`\tan 60\degree=(Z)/(7)`

But tan(60°) = √(3), then:

`\begin{gathered} (Z)/(7)=\sqrt[]{3} \\ \Rightarrow Z=7\sqrt[]{3}\text{ ft} \end{gathered}`