Question

Need help ASAP Which graph shows the asymptotes of the function f(x)= 4x-8 _____ 2x+3

Answer 1

First we will calculate the vertical asymptote, is when the denominator of the function given is equal to zero

`\begin{gathered} 2x+3=0 \\ x=-(3)/(2) \end{gathered}`

then we will calculate the horizontal asymptote because the degree of the numerator and the denominator is equal we can calculate the horizontal asymptote with the next operation

`y=(a)/(b)`

a= the coefficient of the leading term of the numerator

b=the coefficient of the leading term of the denomintor

in our case

a=4

b=2

`y=(4)/(2)=2`
`y=2`

As we can see the graph that shown the asymptotes of the function is the graph in the option C.