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F(x) = 4+x²; f'(-5), f'(0), f'(4)

F(x) = 4+x²; f'(-5), f'(0), f'(4)
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4 votes
F(x) = 4+x²; f'(-5), f'(0), f'(4)

asked
User Onjegolders
by
6.9k points

1 Answer

5 votes

Answer:

f(-5) = 29

f(0) = 4

f(4) = 20

Explanation:

replace the value of the x's of the function with -5, 0 and 4

answered
User Ragoczy
by
7.7k points
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