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What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)​

What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)​
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What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)​

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User Maheshsenni
by
7.5k points

1 Answer

6 votes

Answer:

dt=20.08

Step-by-step explanation:

Q=msdt

840=10*4.184*dt

dt=840/(10*4.184)

dt=20.08

answered
User Appsecguy
by
7.0k points
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