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Solve for b. a = 9 b² c b=±a√3c ​b=±ac√9​ b=±ac√3c b=±3ac−−√

Solve for b. a = 9 b² c b=±a√3c ​b=±ac√9​ b=±ac√3c b=±3ac−−√
asked 107k views
18 votes
Solve for b.

a = 9 b² c




b=±a√3c

​b=±ac√9​

b=±ac√3c

b=±3ac−−√

asked
User Jonathan Bouloux
by
8.5k points

2 Answers

7 votes

b=+ac sqrt 3c

it's b=+ac sqrt 3c

answered
User Ryan Kearney
by
8.5k points
3 votes
b=+ac sqrt 3c
(3rd option!!)
answered
User Reza Ahmadi
by
8.0k points
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