Question

Write square root 3 times square root 6 in the form b square root 2 where b is an integer

Answer 1

3
`√(2)`

Explanation:

using the rule of radicals

`√(a)` ×
`√(b)` ⇔
`√(ab)` , then

`√(3)` ×
`√(6)`

=
`√(3(6))`

=
`√(18)`

=
`√(9(2))`

=
`√(9)` ×
`√(2)`

= 3
`√(2)`