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An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward with the horizontal. What is the magnitude of the velocity when it hits the ground?

An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward with the horizontal. What is the magnitude of the velocity when it hits the ground?
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4 votes
An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward

with the horizontal.
What is the magnitude of the velocity when it hits the ground?

asked
User Tobias M
by
9.0k points

1 Answer

5 votes

Answer:

Step-by-step explanation:

Angle:

β = - 23°

( From the symmetry condition)

An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward-example-1
answered
User Jan
by
7.8k points
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