Question

Find the perimeter P of

JKLM
with vertices J(-4,2), K(1,2), L(2.-2), and M(-3,-2). Round your answer to the nearest tenth, if necessary.
P = units

Answer 1

I have given the procedure how to solve this question you have to draw the Cartesian plane and then connect the dots and measure them and then add all the units.

Refer the attachment .

Answer 2

Answer: P≈18.2 units

Explanation:

`J(-4,2)\ \ \ \ K(1,2)\ \ \ \ L(2,-2)\ \ \ \ M(-3,-2)\\\\\overline{JK}=√((1-(-4))^2+(2-2)^2)\\ \overline{JK}=√((1+4)^2+0^2)\\ \overline{JK}=√(5^2+0)\\\overline{JK}=√(5^2)\\\overline{JK}=5\ units\\\\\overline{KL}=√((2-1)^2+(-2-2)^2) \\\overline{KL}=√(1^2+(-4)^2) \\\overline{KL}=√(1+16)\\ \overline{KL}=√(17) \ units\\\\`

`\overline{LM}=√((-3-2)^2+(-2-(-2))^2)\\ \overline{LM}=√((-5)^2+(-2+2)^2)\\ \overline{LM}=√(25+0^2) \\\overline{LM}=√(25) \\\overline{LM}=5\ units\\\\\overline{JM}=√((-3-(-4))^2+(-2-2)^2)\\ \overline{JM}=√((-3+4)^2+(-4)^2)\\ \overline{JM}=√(1^2+16)\\ \overline{JM}=√(17)\ units\\\\P=5+√(17)+5+√(17) \\\\ P=10+2√(17)\\\\P\approx18.2\ units`