Question

2x^2-19x+9=0 does anyone know the answer

Answer 1

x=1/2,x=9

Explanation:

`2x^(2) -19+9=0\\\\2x^(2) -18x-x+9=0\\\\2x(x-9)-1(x-9)=0\\\\(2x-1)(x-9)=0`

2x-1=0......I

x-9=0.......II

Solving I

2x-1=0

2x=1

x=1/2

Solving II

x-9=0

x=9