Question

79. The table lists the coefficients of kinetic friction

for four materials sliding over steel. A 10-kilogram
block of each of the materials in the table is
pulled horizontally across a steel floor at constant
velocity. Which block would require the smallest
applied force to keep it moving at constant
velocity?

Answer 1

12 kl is correct for this

Answer 2

To determine the material requiring the smallest applied force for a 10-kilogram block sliding at constant velocity, we'll use the formula:

`Frictional Force = Coefficient of Kinetic Friction * Normal Force`

The normal force (N) is equal to the weight of the object

`N = mass * gravity.`

For a 10-kilogram block,

`N = 10 kg * 9.8 m/s^2.`

Let's assume Material A has the lowest coefficient of kinetic friction. The force required (F) is given by:

`F = Frictional Force`

`= Coefficient of Kinetic Friction (Material A) * Normal Force (Weight of the block)`

By plugging in the values, we can calculate the force for each material:

`F_A = Coefficient of A * 10 kg * 9.8 m/s^2`

Repeat this process for Materials B, C, and D. The material with the smallest calculated force will require the least applied force to maintain constant velocity.