In the form of y=m+c give the equation of the line that passes through (6,3) and (12,5) Second time posting this question so if anyone can help it would be much appreciated

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asked Sep 2, 2023 169k views

1 Answer

Kingof · Answer 1 · 2023-09-06T10:35:51+0000

first find the gradient between the two points.

$(y2-y1)/(x2-x1) \\=(5-3)/(12-6) \\=(2)/(6) \\m=(1)/(3)$

I will use the pointy (6,3) to get the value of c meaning I will plug n the points in the general equation together with the gradient.

$3=(1)/(3) (6)+c\\3=2+c\\c=3-2\\c=1$

y=(1)/(3)x+1