Question

I need more help on other questions! Same assignment

Answer 1

a.
`(10)/(3)`

b.
`(4)/(3)`

c.
`4(2)/(3)`

Explanation:

a.

`\mathrm{Convert\:mixed\:numbers\:to\:improper\:fraction:}\:a(b)/(c)=(a\cdot \:c+b)/(c)`

`3(1)/(2)=(3\cdot 2+1)/(2)=(7)/(2)`

b.

reciprocal is technically the opposite

c.

`\mathrm{Convert\:mixed\:numbers\:to\:improper\:fraction:}\:a(b)/(c)=(a\cdot \:c+b)/(c)`

`=(7)/(2)/ (3)/(4)`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(b)/ (c)/(d)=(a)/(b)* (d)/(c)`

`=(7)/(2)* (4)/(3)`

`\mathrm{Cross-cancel\:common\:factor:}\:2`

`=(7)/(1)* (2)/(3)`

`\mathrm{Multiply\:fractions}:\quad (a)/(b)* (c)/(d)=(a\:* \:c)/(b\:* \:d)`

`(7* \:2)/(1* \:3)`

`\mathrm{Multiply\:the\:numbers:}\:7* \:2=14`

`=(14)/(1* \:3)`

`\mathrm{Multiply\:the\:numbers:}\:1* \:3=3`

`=(14)/(3)`

`\mathrm{Convert\:improper\:fraction\:to\:mixed\:numbers}`

`4(2)/(3)`