Question

A line has a slope of 1/10 and passes through the point (-10, 4). What is its equation in slope-intercept form? Write your answer using integers, proper fractions, and improper fractions in simplest form.​

Answer 1

`(\stackrel{x_1}{-10}~,~\stackrel{y_1}{4})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{10} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ \cfrac{1}{10}}(x-\stackrel{x_1}{(-10)}) \implies y -4= \cfrac{1}{10} (x +10) \\\\\\ y-4=\cfrac{1}{10}x+1\implies {\LARGE \begin{array}{llll} y-\cfrac{1}{10}x+5 \end{array}}`