Question

11.) The sum of four consecutive even

integers is 68. Find the four consecutive
even integers. What is the 3rd integer
in the sequence?

Answer 1

• Four consecutive even integers are 14, 16, 18 and 20
  
• Third number in the sequence is 18
  

Explanation:

Let N be the first even integer

Each consecutive integer is 2 away from the previous integer

Next consecutive integer = N + 2, next one = N+4 and the last one = N +6

Add these expressions together, set them equal to 68 to solve for N

==> N + (N +2) + (N +4) + (N + 6) = 68

==> N + N +2 + N +4 + N + 6 = 68

==> 4N + 12 = 68

==> 4N = 68-12

==> 4N = 56

N = 56/4 = 14

So the integers are 14, 16, 18 and 20

Third integer in the sequence is 18