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Factorise completely m^2n-mn^2

Factorise completely m^2n-mn^2
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Factorise completely m^2n-mn^2

asked
User HexAndBugs
by
8.5k points

1 Answer

5 votes

Answer: nm(m-n)

Explanation:

m^2n-mn^2=

n*m(m)-m*n(n)=

n*m(m-n)=nm(m-n)

answered
User Jackytse
by
8.0k points
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