Question

Factor the expression C^(2)-5c+9=0

Answer 1

Answer:
`\boxed{\left(c-(5)/(2)-(i√(11))/(2) \right)\left(c-(5)/(2)+(i√(11))/(2) \right)}`

Explanation:

Using the quadratic formula to find the roots of the equation,

`c=(-(-5) \pm √((-5)^2 -4(1)(9)))/(2(1))\\\\c=(5)/(2) \pm (i√(11))/(2)`

So,

`c^2 -5c+9=\boxed{\left(c-(5)/(2)-(i√(11))/(2) \right)\left(c-(5)/(2)+(i√(11))/(2) \right)}`