Question

The barometer at an indoor pool reads 105.00 kPa. If the temperature in the room is 26c, what is the patial pressure of the "dry" air??

a. 30.88 kPa
b. 101.60 kPa
c. 108.40 kPa
d. 357.00 kPa

Answer 1

Option B. 101.60 KPa

Step-by-step explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 105.00 KPa

Partial pressure of wet gas (Pᵥᵥ) at 26 °C = 3.4 KPa

Partial pressure of dry gas (Pₔ) =?

Total pressure = partial pressure of dry gas + partial pressure of wet gas

Pₜ = Pₔ + Pᵥᵥ

105 = Pₔ + 3.4

Collect like terms

105 – 3.4 = Pₔ

Pₔ = 101.60 KPa

Therefore, the partial pressure of the dry gas is 101.60 KPa