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F X ∼ B (10, 0.5 ) ( X is Binomial with n=10, p=0.5) P(X = 9) = (3 decimals) X ∼ B (3, 0.5 ) P(X=1)= (3 decimals) X ∼ B (4, 0.5) , P(2 ≤ X ≤ 3) = (3 decimals)

F X ∼ B (10, 0.5 ) ( X is Binomial with n=10, p=0.5) P(X = 9) = (3 decimals) X ∼ B (3, 0.5 ) P(X=1)= (3 decimals) X ∼ B (4, 0.5) , P(2 ≤ X ≤ 3) = (3 decimals)
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F X ∼ B (10, 0.5 ) ( X is Binomial with n=10, p=0.5)

P(X = 9) =

(3 decimals)

X ∼ B (3, 0.5 )

P(X=1)=

(3 decimals)

X ∼ B (4, 0.5) ,

P(2 ≤ X ≤ 3) =

(3 decimals)

asked
User Teymour
by
8.8k points

1 Answer

12 votes

Answer:

r awver e

Explanation:

w warw rwq

answered
User Emirc
by
8.2k points
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