Question

Fathers age is twice his daughter age but 16 years ago fathers age was 4 times his daughters age . Calculate their ages

Answer 1

Father's age = 48

Daughter's age = 24

Explanation:

Let x be father's age and y be daughter's age.

1st equation:

x = 2y

2nd equation:

(x - 16) = 4(y - 16)

Replacing value of x from 1st equation,

(2y - 16) = 4(y - 16)

2y - 16 = 4y - 64

4y - 2y = 64 - 16

2y = 48

y = 48/2

y = 24

And,

x = 2y

x = 2 x 24

x = 48

8x - x = 64 - 16

7x = 48