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Which answer represents the series in sigma notation? 1+12+14+18+116+132+164 ∑j=1712(j+1) ∑j=17(12)j−1 ∑j=1712j+1 ∑j=172j−1
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Which answer represents the series in sigma notation? 1+12+14+18+116+132+164 ∑j=1712(j+1) ∑j=17(12)j−1 ∑j=1712j+1 ∑j=172j−1
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Oct 25, 2022
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Which answer represents the series in sigma notation?
1+12+14+18+116+132+164
∑j=1712(j+1)
∑j=17(12)j−1
∑j=1712j+1
∑j=172j−1
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Michael Wheeler
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Answer: The answer is the second one: ∑j=17(12)j−1
Explanation:
Ethan Vu
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Ethan Vu
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