Question

What is the length of the hypotenuse of the triangle when x = 9?

7x +41
5x
The length of the hypotenuse is about
(Round to the nearest tenth as needed.)

I NEED THIS ASAP

Answer 1

`H = 53.30`

Explanation:

Given

`Side\ 1 = 7x + 41`

`Side\ 2 = 5x`

Required

Determine side x

The hypotenuse (H) is calculated using:

`H^2 = Side\ 1^2 + Side\ 2^2`

`H^2 = (7x + 41)^2 + (5x)^2`

Substitute 9 for x:

`H^2 = (7*9 + 41)^2 + (5*9)^2`

`H^2 = 10816 + 2025`

`H^2 = 12841`

So:

`H = \sqrt {2841`

`H = 53.30`