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Solve the quadratic equation 2x^2-5x+1=x+4​

asked
User Spulec
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1 Answer

9 votes

Answer:

Explanation:

Combine like terms in 2x^2-5x+1=x+4: 2x^2 -6x - 3 = 0

The coefficients of this quadratic are {2, -6, -3}. Apply the quadratic formula. Start by finding the discriminant, b^2 - 4ac:

b^2 - 4ac = (-6)^2 - 4(2)(-3) = 36 + 24 = 60

Because the discriminant (60) is positive, we know that this quadratic has two real, unequal roots:

-(-6) ± √60 6 ± (√4)(√15)

x = -------------------- = ----------------------

2(2) 4

or:

6 ± 2√15 3 ± √15

x = ----------------- = ----------------

4 2

answered
User LtlBeBoy
by
8.2k points

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