Answer:
R=1
Explanation:
R ∝ p^2 /t
If we introduce proportionality constant K, we have
R = Kp^2 /t .......eqn(1)
When p= 8 and t = 16, R = 8
Substitute values of p,t, R into eqn(1)
8= (K × 8^2 )/ 16
8= 64K/16
64K= 16×8
64K= 128
K=2
What is the value of R when p =4 and t = 32
R = Kp^2 /t
R=( 2 × 4^2) /32
= 32/32
R=1