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2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2 If 6.0 moles of KCl are produced, how many moles of HCl were reacted?

2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2 If 6.0 moles of KCl are produced, how many moles of HCl were reacted?
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2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2 If 6.0 moles of KCl are produced, how many moles of HCl were reacted?

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User Lawrence Barsanti
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1 Answer

7 votes

Answer:

2x - 9y = 23

5x - 3y = -12x - 9y = 23

5x - 3y = -1

Step-by-step explanation:

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User Stepio
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User Fede
asked Apr 25, 2022 151k views
2KMnO4 + 16HCl -> 5Cl2 + 2KCl + 2MnCl2 + 8H2O If 6.0 moles of KCl are produced, how many moles of HCl were reacted?
Fede asked Apr 25, 2022
by Fede
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