Question

Determine the number of molecules of OF2 and moles of fluorine contained in 5.53 moles of OF2.

Answer 1

Answer:
`33.31* 10^(23)` molecules of
`OF_2`

and 11.06 moles of Flourine

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

1 mole of
`OF_2` contains=
`6.022* 10^(23)` molecules of
`OF_2`

Thus 5.53 moles of
`OF_2` contains=
`(6.022* 10^(23))/(1)* 5.53=33.31* 10^(23)` molecules of
`OF_2`

1 mole of
`OF_2` contains= 2 moles of Flourine

5.53 moles of
`OF_2` contains=
`(2)/(1)* 5.53=11.06` moles of Flourine