Question

find the equation for the line that passes through the point (4,-3), and that is perpendicular to the line with the equation y= -3/4x-3​

Answer 1

hi

Explanation:

Answer

Slope between two given points (1,3) and (2,7) is

m=

2−1

7−3

​

=4

Then perpendicular slope is m

1

​

=

4

−1

​

The line equation with this slope is given by

y=

4

−1

​

x+c.......(1)

Now, the above line passes through the point (−4,−3)

⇒−3=

4

−1

​

×(−4)+c

⇒c=−4

Therefore required line is 4y+x+16=0 (Substitute

′

c

′

in (1) and simplify)