Question

Help me please omg

Answer the following question:

How many moles of ammonia are in 375. mL of a 2.25 M aqueous ammonia solution?

Find the numerical answer for this question and make sure to include the following:

What is the chemical formula for ammonia?
What is the formula for molarity?
When you give your numerical answer, what is the correct significant figures and how do you know that is the correct amount?

Answer 1

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Step-by-step explanation:

Step 1: Given and required data

• Volume of solution (V): 375. mL

• Molar concentration of the solution (M): 2.25 M

• Chemical formula for ammonia: NH₃

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)