Question

What is the force on a 1025 kg elevator that is falling freely at 9.8 m/sec 2?

Answer 1

Given :-

• Mass = 1025 kg
• Acceleration = 9.8 m/s²

To Find :-

Force

Solution :-

We know that

F = mg

F = 1025 × 9.8

F = 10,045 N

Or,

10045/1000 = 10.045 Kilo Newton

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