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Y=1+sinx/cosx find dy/dx

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Y=1+sinx/cosx find dy/dx

asked Dec 19, 2022 6.8k views

6 votes

Y=1+sinx/cosx find dy/dx

Mathematics
college

Flyingfox asked

8.6k points

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1 Answer

9 votes

Anwser:

X=1539 I think

Sec answered Dec 25, 2022

by Sec

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Implicit differentiation: ycosx=x^2+y^2 Derivative of both sides: =((y)(-sinx)+(cosx)(dy/dx)=2x+2y(dy/dx) =(-ysinx+cosx(dy/dx)=2x+2y(dy/dx) =cosx(dy/dx) - 2y(dy/dx) = ysinx+2x =(cosx-2y)dy/dx = ysinx+2x

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