Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = -16x^2 + 148x + 128

Answer 1

10.05

Explanation:

-16x2+148x+128=0 (we can divide out a -4 )

4x2-37x-32=0, (now use the quadratic formula)

(37±sqrt(372-4(4)(-32))/(2*4)=x, x=10.046 & x=-.796