Old MacDonald had a farm. On this farm he had some cows and chickens. When he “took stock” (counted), the farmer had 15 animals and 44 legs. How many cows and chickens did Old M…

Question

asked Jan 16, 2022 227k views

2 Answers

LiorH · Answer 1 · 2022-01-21T22:53:42+0000

Answer:

Explanation:

let x be chickens and y be cows

x+y=15

x=15-y

2x+4y=44, using x=15-y

2(15-y)+4y=44

30-2y+4y=44

2y+30=44

2y=14

y=7, since x=15-y

x=8

So there are 8 chickens and 7 cows.