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At 273K, the speed of an H2 molecule is 1.84*103 m/s.

At what temperature will urms be 2.9 times that value?
Give the answer in K

1 Answer

6 votes
To find the temperature at which the root mean square speed (urms) of an H2 molecule is 2.9 times the given value, we can use the relationship between temperature and urms.

The root mean square speed is directly proportional to the square root of the temperature.

Let's denote the initial temperature as T1 and the final temperature as T2.

According to the given information, urms at T1 is 1.84*10^3 m/s.

To find T2, we can use the equation:

(urms at T2) = 2.9 * (urms at T1)

Taking the square of both sides and solving for T2:

(T2 / T1) = (2.9^2)

T2 = (2.9^2) * T1

Substituting the given value of T1 and calculating T2:

T2 = (2.9^2) * 273 K

T2 ≈ 2,238 K

Therefore, the temperature at which urms will be 2.9 times the initial value is approximately 2,238 K.
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User Rombarcz
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