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How many moles of calcium hydroxide, Ca(OH)2 are needed to neutralize 2 moles of acetic acid, CH3CO2H? a. 1 b. 2 c. 4 d. 8

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Final answer:

In a neutralization reaction, one mole of calcium hydroxide, Ca(OH)2, can neutralize one mole of acetic acid. Therefore, to neutralize 2 moles of acetic acid, you need 2 moles of Ca(OH)2. The correct response is answer choice b ('2').

Step-by-step explanation:

The question asks how many moles of calcium hydroxide, Ca(OH)2, are needed to neutralize 2 moles of acetic acid, CH3CO2H. To answer this, we need to understand the nature of the reaction between these substances.

In a neutralization reaction, an acid reacts with a base to form water and a salt. The reaction between acetic acid and calcium hydroxide can be represented as CH3CO2H + Ca(OH)2 → Ca(CH3CO2)2 + 2H2O. Looking at the equation, you can see that one mole of calcium hydroxide is able to neutralize one mole of acetic acid. Therefore, to neutralize 2 moles of acetic acid, you would need 2 moles of calcium hydroxide. So, the correct answer is b. 2.

Learn more about Neutralization Reactions

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User Brian Boyle
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