Question

Two forces A and B act on a 21.0-kg object on a frictionless tabletop, as shown in the figure. If A = 17.0 N and B = 10.1 N, find the net force on the object and its acceleration. In the box below enter the net force in Newtons and the acceleration in meters per second squared.

Answer 1

The net force on the object acted upon by two forces (17.0 N and 10.1 N) is 27.1 N. Using Newton's second law, the acceleration of the object is calculated to be approximately 1.29 m/s².

Step-by-step explanation:

The question is asking about the net force and the acceleration of an object under two different forces. Given that the forces are A = 17.0 N and B = 10.1 N, the net force on the object can be calculated as the vector sum of these two forces, which in this case is simply 17.0 N + 10.1 N = 27.1 N. The acceleration can be calculated using Newton's second law F = ma. Substituting the given values into the equation, we find a = F/m = 27.1 N / 21.0 kg = 1.29 m/s².

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