To solve the equation x^2 - 15x - 39 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = -15, and c = -39. Plugging these values into the quadratic formula, we get:
x = (15 ± √((-15)^2 - 4(1)(-39))) / (2(1))
x = (15 ± √(225 + 156)) / 2
x = (15 ± √381) / 2
Now, let's approximate the solutions to the nearest tenth using a calculator:
x ≈ (15 + √381) / 2 ≈ 14.8
x ≈ (15 - √381) / 2 ≈ 0.2
Therefore, the solutions to the equation x^2 - 15x - 39 = 0, rounded to the nearest tenth, are approximately x ≈ 14.8 and x ≈ 0.2.