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A function is defined using the formula y=(1)/(3)x+5.If the domain of the function is {-12,9,18}, then which of the following is not an element of the function's range?

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Final answer:

To find which value is not in the range of the function y=(1/3)x+5 with domain {-12,9,18}, we calculate y for each x, resulting in a range of {1, 8, 11}. Any value outside of these is not in the range.

Step-by-step explanation:

The question pertains to identifying which value is not in the range of a given function when the domain is specified. The function in question is y = (1/3)x + 5, and the domain provided is {-12, 9, 18}. To determine the range, we calculate the value of y for each x in the domain:

  • For x = -12: y = (1/3)(-12) + 5 = -4 + 5 = 1
  • For x = 9: y = (1/3)(9) + 5 = 3 + 5 = 8
  • For x = 18: y = (1/3)(18) + 5 = 6 + 5 = 11

Therefore, the range of the function for the given domain is {1, 8, 11}. Any number that is not one of these three is not an element of the function's range for the specified domain.

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User RK Poddar
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