Question

A game is played using one die. If the die is rolled and shows 2,the player wins $15. If the die shows any other number besides 2 the player wins nothing, There is a charge of $3.00 to play this game. Make the probability distribution for this game.

Answer 1

expected to lose $1.50 on average each time they play the game.

Explanation:

Sure. The probability distribution for the game is as follows:

Outcome | Probability

------- | --------

Win | 1/6

Lose | 5/6

This means that the player has a 1/6 chance of winning $15 and a 5/6 chance of losing nothing.

The expected value of the game is negative, meaning that the player is expected to lose money in the long run. This is because the probability of winning is low and the cost of playing is high.

The expected value of a game is calculated by multiplying the probability of each outcome by the value of that outcome and then summing the results. In this case, the expected value is:

```

Expected value = (1/6 * $15) - $3 = -$1.5

```

This means that the player is expected to lose $1.50 on average each time they play the game.

Therefore, the player should not play this game, as they are expected to lose money in the long run.