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This math question help me now

This math question help me now-example-1
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User Hyeomans
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2 Answers

2 votes

A) 7/9

To simplify the prime factorization of the fraction 49/63, we can find the prime factorization of both the numerator (49) and the denominator (63) separately and then simplify.

Prime factorization of 49:

49 is equal to 7 * 7, so its prime factorization is 7^2.

Prime factorization of 63:

63 can be factored as 7 * 9, and further, 9 is 3 * 3. So, the prime factorization of 63 is 7 * 3 * 3.

Now, let's simplify the fraction:

49/63 = (7^2) / (7 * 3 * 3)

We can cancel out a common factor of 7 between the numerator and denominator:

49/63 = (7 * 7) / (7 * 3 * 3)

Now, cancel the common factor of 7:

49/63 = (7 * 7) / (7 * 3 * 3) = (7/7) * (7/3) * (1/3)

Now, you have a simplified fraction:

49/63 = (1) * (7/3) * (1/3)

Multiply the numerators and denominators:

49/63 = (7/9)

So, the simplified prime factorization of 49/63 is 7/9.

Hope this helps. If you don't understand pls ask. I'll be happy to help

answered
User Edward Van Kuik
by
8.1k points
5 votes

Answer:

  1. d
  2. b
  3. a

Explanation:

You want the steps of the process for simplifying 49/63 by prime factorization.

Prime factors

The prime factors of the numbers involved are ...

49 = 7·7

63 = 3·3·7

Simplification

The process of simplifying the fraction is ...


(49)/(63)=(7*7)/(3*3*7)\qquad\text{d. show prime factors}\\\\\\=(/\!\!\!7*7)/(3*3*/\!\!\!7)\qquad\text{b. cancel common factors}\\\\\\=(7)/(9)\qquad\text{a. result}

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answered
User Petike
by
9.0k points

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