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A 13 kg mass object initially has 2500 J of kinetic energy -1200 J of net work is done on the object by force opposite the direction of the object motion what is the final speed of the object

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User NoelC
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1 Answer

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Step-by-step explanation:

2500 - 1200 = 1300 J of KE at end

KE = 1/ 2 m v^2

1300 = 1/2 (13) v^2

v = 14.1 m/s

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User Delrius Euphoria
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