There are two moments where the object is in position 8: in t = 15 and t = -1. 
 
 To find the moment when object is at position 8 , just match the (t) a function A 8 and resolve to t . First, we subtracted 8 on both sides of the equation to put it in standard form: 
 t² - 14t - 15 = 0 
 
 Now we can use a quadratic formula to solve: 
 t = (-b ± √ (b² - 4ac))/(2a) 
 
 Replacing the values of A, B and C, we get: 
 t = (-(-14) ± √ ((-14) ²-4 (1) (-15)))) / (1 (1 )) 
 t = (14 ± √256)/2 
 t = (14 ± 16)/2 
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