Function values in the specified times are:
- for t = 0, f (t) = 0
- for t = 1.5, f (t) = 1.125
- For t = 2, f (t) = 1
- to t = 3, f (t) = 0
Second degree equation:
A Second Degree Equation is an equation in which the unknown variable (generally denoted as x) is raised to the square (Exontente 2) and may also include terms linear and constant. The overall form of a high school equation is ax² + bx + c = 0 . of the ball equals f (t) = -0.5t² + 1.5t . With this, to find the value of the function in times, we must perform the replacement of each time instead of t in the function. From the function in the specified times, we have:
for t = 0:
f (0) = -0.5 (0)^2 + 1.5 (0)
f (0) = 0
t = 1.5:
f (1.5) = -0.5 (1.5)^2 + 1.5 (1.5)
f (1.5) = -0.5 (2.25) + 2.25
f (1.5) = -1.125 + 2.25
f (1.5) = 1.125
For t = 2:
f (2) = -0.5 (2)^2 + 1.5 (2)
f (2) = -0.5 (4) + 3
f (2) = -2 + 3
f (2) = 1
For t = 3:
f (2) = 1
f (3) = -0.5 (3)^2 + 1.5 (3)
f (3) = -0.5 (9) + 4, 5
f (3) = -4.5 + 4.5
f (3) = 0
Therefore, the function values in the specified times are:
- for t = 0, f (t) = 0
- for t = 1.5 , f (t) = 1.125
- For t = 2, f (t) = 1
- for t = 3, f (t) = 0