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In how many ways can 8 books be chosen from a group of 9

asked
User Nannette
by
8.4k points

2 Answers

3 votes

Answer:

because the present of group is not as ame as books

the value of the book is =8

the value of the group is = 9

90×80=7,200

by the value of 8×9=72

; 72/7,200

answered
User Dick Eshelman
by
8.7k points
5 votes

Final answer:

There are 9 ways to choose 8 books from a group of 9, calculated using the combinations formula C(9, 8) = 9! / [(9-8)! 8!] = 9.

Step-by-step explanation:

The question posed is related to combinatorics, a topic in mathematics. Specifically, the student is asking about the number of ways to choose 8 books from a group of 9. To calculate this, we use combinations because the order in which we select the books does not matter. Given 9 books, the number of ways to choose 8 out of them can be represented by 9 choose 8, which is denoted by the formula C(n, k) = n! / [(n-k)! k!] where n is the total number of items, and k is the number of items to be chosen.

Using the formula, we calculate the number of combinations as follows:

  1. Here, n is 9 and k is 8.
  2. So, C(9, 8) = 9! / [(9-8)! 8!] = 9.
  3. Therefore, there are 9 ways to choose 8 books from a group of 9.

answered
User Joy
by
8.3k points

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