What is the electric potential at a point 6 m below a 1.2 nc charge?

Question

asked Apr 7, 2024 204k views

2 Answers

Zmey · Answer 1 · 2024-04-09T02:40:02+0000

The electric potential at a point 6 m below a 1.2 nC charge is 1.8 MV.

The electric potential at a point below a charge can be calculated using the formula:

V = k * Q / r

Where:

In this case, the charge is 1.2 nC (1.2 x 10^-9 C) and the distance is 6 m. Substituting these values into the formula, we get:

V = (9 x 10^9 Nm^2/C^2) * (1.2 x 10^-9 C) / 6 m = 1.8 x 10^9 Nm/C = 1.8 MV

Travis Christian · Answer 2 · 2024-04-13T07:57:42+0000

The electric potential at the point is 1.8V

Electric potential is the electric potential energy per unit charge at a point in space. It is a scalar quantity measured in volts.

A positive charge moves from higher to lower potential, while a negative charge moves in the opposite direction.

It is expressed as

V = kq/r

where K = 9 × 10⁹

q = 1.2nC = 1.2× 10⁻⁹

r = 6m

therefore

V = 9 × 10⁹ × 1.2× 10⁻⁹/6

V = 1.8V

Therefore, the electric potential at the point is 1.8V