Final answer:
The solution set of the given system of equations is (-6, 29) and (4, -11).
Step-by-step explanation:
The given system of equations is:
y = x^2 − 2x − 19
y + 4x = 5
To find the solution set, we can substitute the value of y from the second equation into the first equation:
x^2 - 2x - 19 + 4x = 5
Simplifying the equation, we get:
x^2 + 2x - 14 = 0
Factoring or using the quadratic formula, we find that x = -6 or x = 4.
Substituting these values of x back into the second equation, we can find the corresponding values of y:
When x = -6, y + 4(-6) = 5, which gives y = 29.
When x = 4, y + 4(4) = 5, which gives y = -11.
Therefore, the solution set of this system of equations is (-6, 29) and (4, -11).